False Proof – 2 = 4, As the Limit of an Infinite Power Tower
Creators
Problem: Prove that $ 2 = 4$. Solution: Consider the value of the following infinitely iterated exponent: $$\displaystyle \sqrt{2}^{\sqrt{2}^{\sqrt{2}^{\cdot^{\cdot^{\cdot}}}}}$$ Let $ a_n = \sqrt{2} \uparrow \uparrow n$, that is, the above power tower where we stop at the $ n$-th term. Then $ a_n$ is clearly an increasing sequence, and moreover $ a_n \leq 4$ by a trivial induction argument: $ \sqrt{2} \leq 4$ and if $ a_n \leq 4$ then $ a_{n+1} = (\sqrt{2})^{a_n} \leq (\sqrt{2})^{4} = 4$.
Additional details
Description
Problem: Prove that $ 2 = 4$. Solution: Consider the value of the following infinitely iterated exponent: $$\displaystyle \sqrt{2}^{\sqrt{2}^{\sqrt{2}^{\cdot^{\cdot^{\cdot}}}}}$$ Let $ a_n = \sqrt{2} \uparrow \uparrow n$, that is, the above power tower where we stop at the $ n$-th term.
Identifiers
- UUID
- d873e051-5c17-4def-846d-964abef5c924
- GUID
- https://www.jeremykun.com/2012/05/05/false-proof-2-4-as-the-limit-of-an-infinite-power-tower/
- URL
- https://www.jeremykun.com/2012/05/05/false-proof-2-4-as-the-limit-of-an-infinite-power-tower
Dates
- Issued
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2012-05-05T16:06:34
- Updated
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2012-05-05T16:06:34